&
Expand the function 'Sinx by
Maclaurined theorem
Answers
Answered by
2
Step-by-step explanation:
f(x)= sinx
By Maclaurin's : x=a=0
also expansion is:
f(x)= f(0) + x f'(0) + (x^2/2!) f''(0) + (x^3/3!) f'''(0) +...
f(x)= sinx f(0)=0
f'(x)= cosx f'(0)=1
f''(x)= - sinx f''(0)=0
f'''(x)= - cosx f'''(0)= - 1
f(x)=0 + 1 +(x^2/2)(0) +(x^3/3)( -1)+...
= 1 - (x^3)/3...
Similar questions