& find no of atoms in 40gm of helium
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Answer:
1 mole of He contains 6.023×10^23 atoms. 1 mole of He = 4 gm of He. So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.
so 40 gm contains 2(3.011×10^24) He atoms
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Explanation:
1 mole of He contains 6.023×10^23 atoms. 1 mole of He = 4 gm of He. So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.
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