Question

& Find the cost of polishing a circular table-top of diameter 1.6 m, if
the rate of polishing is 15/m2. (Take 3.14)
​

Answer 1

$\huge \mathbb \purple{QUESTION}$

Find the cost of polishing a circular table-top of diameter 1.6m, if the rate of polishing is 15/m². (π = 3.14)

$\huge \mathbb \purple{SOLUTION}$

We have, diameter $= 1.6m$

Radius$= \frac{1.6}{2} = 0.8m$

Area of table-top to be polished $= \pi r ^{2}$

$= 3.14 \times (0.8) ^{2}$

$= 3.14 \times 0.8 \times 0.8$

$= 2.0096m ^{2}$

→ Area of table-top $= 2.0096m ^{2}$

→ Cost of polishing of 1m² = Rs. 15

→ Cost of polishing the table-top

$\sf{ = rs.15 \times 2.0096 = rs.30.144 \: or \: rs.30}$

Hope It Helps You!!....

Answer 2

Answer:

Diameter = 1.6 m

∴ Radius = 1.62 = 0.8 m

Area of the table-top = πr square

= 3.14 × 0.8 × 0.8 m square

= 2.0096 m square  

∴ Cost of polishing = ₹ 15 × 2.0096

= ₹ 30.14 (approx.)

Step-by-step explanation:

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