Question

&
If 4 cot 0 = 3, then find the values of
tan o, seco and cosec o.​

Answer 1

Answer:

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Answer 2

ans :

4 cot 0 = 3

cot 0 = 3/4 = base/perpendicular

Base = 3. (BC)

Perpendicular = 4. (AB)

let AC be hypotenuse

by pythagoras theorem :

(AC)^2 = (AB)^2 + (BC)^2

(AC)^2 = (4)^2 + (3)^2

(AC)^2 = 16 + 9

(AC)^2 = 25

AC = √25

AC = 5

tan 0 = perpendicular / base

= 4/3

sec 0 = hypotenuse / base

= 5/3

cosec 0 = hypotenuse / perpendicular

= 5/4

Hope this helps you