Question

& If your weight on the earth is 60 Kg, then how far you will have to go from the centre earth, so that your weight is reduced to 30 Kg?​

Answer 1

Explanation:

The equation is F = G(m1)(m2)/r^2, where m1 is the mass of Earth, m2 is 60kg, G is the gravitational constant, and r is the distance from the center of mass.

Right now - F (in newtons) is 60 x 9.8m/s = 548N at the surface; So:

548N = G(m1)(60kg)/r^2. Since G, m1, and m2 are all the same and only r is going to change, let’s make G x m1 x m2 a constant K, and make r = 1 Earth radius.

548N = K/1, so K is 548…

For 1/2 the weight, that would be 274N = 548/r^2; or

r^2 = 548/274

r^2 = 2

r = sqrt(2)… So, you’d need to be about 1.414 x the distance of Earth’s radius for your weight to be about half… Earth’s radius is 6,371km , so that’s

1.414 x 6,371 = 9,008km - 6371km = 2,638km further out from the surface.