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The perimeter of a rectangle is 40 cm and its area is 96 sq.cm. Calculate its length and breadth.
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2(l+b)=40
l×b=96
l=96/b
2(96/b+b)=40
2(96+b^2/b)=40
96+b^2=40b/2
b^2+96=20b
b^2-20b+96=0
b^2-12b-8b+96=0
b(b-12)-8(b-12)=0
b=8 or 12
if b=8. if b=12
l=96/8. l=96/12
=12. l=8
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