Question

&
The third term of an AP
art is 32 and its
fifth term is 40 find
the sum of first
terms
of the
thirty terms of AP​

Answer 1

Answer:

The sum of first 30 terms is 2460

Step-by-step explanation:

given that

a_3 = 32\\a+2d=32..(1)\\a_5 = 40\\a+4d=40..(2)

solving 1 and 2 by elimination method we get

d= 4

a= 24

then sum of first 30 terms  

S_3_0 = \frac{n}{2}(2a+(n-1)d)\\\\S_3_0 = \frac{30}{2}(2(24)+(30-1)4)\\\\S_3_0 = 15(48+(29\times 4))\\\\S_3_0 = 15(48+116)\\\\S_3_0 = 15(164)\\\\S_3_0 = 2460

hence , the sum of first 30 terms is 2460

#Learn more:

In an ap the sum of first term third term and fifth term is 39

brainly.in/question/13040422

Step-by-step explanation:

Answer 2

Answer:

The sum of the first 30 terms is 2460.

Step-by-step explanation:

given that:

a₃=32

or  a+2d=32 ---------------(i)

a₅=40

or  a+4d=40 ----------------(ii)

On subtracting (i) from (ii), we get 2d=8

or  d=4

Now,

a+2d=32

a+8=32

a=24

then sum of first 30 terms :

S₃₀=$\frac{n}{2}$[2a+(n-1)d]

S₃₀=$\frac{30}{2} [2*24+29*4]$

S₃₀=15(48+116)

S₃₀=15*164

S₃₀=2460.

Hence, the sum of first 30 terms in 2460.

Mark as the brainliest buddy!