Question

& Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
​

Answer 1

Answer:

9,10,11

Step-by-step explanation:

2(n)+3(n+1)+4(n+2)=74

7n+11=74

7n=63

n=9

Answer 2

Answer:

7, 8, 9

Step-by-step explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9