& Two Sphere A and B weight is 2009 and 300N
Resp. approach each otheo caith veloilies amis
and 2m/s Resp. positive In the coefficient of
Restitution is 0:6 D find the velocity just aftex
impact. 2) Loss of energy during Impact
mic
Answers
Answer:
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Answer:
Let m
1
be the mass of one sphere, ν
1i
be its velocity before the collision, and ν
1f
be its velocity after the collision. Let m
2
be the mass of the other sphere, ν
2i
be its velocity before the collision, and ν
2f
be its velocity after the collision. Then, according to Eq.9−75
ν
1f
=
m
1
+m
2
m
1
−m
2
ν
1i
+
m
1
+m
2
2m
2
ν
2i
.
Suppose sphere 1 is originally traveling in the positive direction and is at rest after the collision. Sphere 2 is originally traveling in the negative direction. Replace ν
1i
with ν,ν
2i
with −ν and ν
1f
with zero to obtain 0=m
1
−2m
2
. Thus ,
m
2
=m
1
/3=(300g)/3=100g .
(b) We use the velocities before the collision to compute the velocity of the center of mass:
ν
com
=
m
1
+m
2
m
1
ν
1i
+m
2
ν
2i
=
300g+100g
(300g)(2.00m/s)+(100g)(−2.00m/s)
=1.00m/s .