Question

& Using the information given in the adjoining figure show that:
(1) PR > SR
(11) PQ > PS​

Answer 1

Step-by-step explanation:

in triangle PQS

Angle QPS is equal to angle PQS is equal to 50°

so angle QSP is 80° by angle sum property

By linear pair angle RSP is 100°

In triangle PS is equal to SR

Angle SPR is equal to angle SRP (angle opp to equal side are equal )

Angle spr and angle srp is 40°

Angle RSP is greater than angle SRP

so PR >SR

SimilarlyPQ>PS

Answer 2

Answer:

1). In ▴PSR, ∠PSR=100°,∠P=∠R=40

Since PR >SR[Side opposite to greater angle]

2).In▴PQS,∠P=Q=50°,∠PSA=80°

Since PQ>PS [Side opposite to greater angle]