Question

&
Zeroes
find the zeroes
of the following polynomials and verify
between
the
the relationship
and the coefficient
of the terms,
P(x) x² – 8x +12​

Answer 1

Step-by-step explanation:

=x²-(6+2)x+12

=x²-6x-2x+12

=x(x-6)-2(x-6)

=(x-2) (x-6)

(x-2)=0. (x-6)=0

x=2. x=6

Let alpha=2. and Beeta=6

Sum of zeroes=-b/a

2+6. = 8/1

8=8

Product of zeroes=c/a

2×6 =12/1

12=12