Question

Amphoteric nature of beryllium hydroxide equations

Answer 1

Heyy mate here is your answer....

Beryllium hydroxide, Be(OH)2, is anamphoteric hydroxide, dissolving in both acids and alkalis. ... The naturalpure beryllium hydroxide is rare (in form of the mineral behoite, orthorhombic) or very rare (clinobehoite, monoclinic). When alkali is added to beryllium salt solutions the α-form (a gel) is formed.

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Answer 2

Answer: The equations showing amphoteric nature of beryllium hydroxide is given below.

Explanation:

Amphoteric nature of the compound means that, the compound react with both acid and base to produce salt.

We are given a chemical compound of beryllium hydroxide having cheical formula of $Be(OH)_2$

• Reaction with base:

The chemical equation for the reaction of beryllium hydroxide with sodium hydroxide follows:

$Be(OH)_2+2NaOH\rightarrow Na_2[Be(OH)_4]$

By Stoichiometry of the reaction:

1 mole of beryllium hydroxide reacts with 2 moles of sodium hydroxide to produce 1 mole of sodium beryllate.

• Reaction with acid:

The chemical equation for the reaction of beryllium hydroxide with hydrochloric acid follows:

$Be(OH)_2+2HCl\rightarrow BeCl_2+2H_2O$

By Stoichiometry of the reaction:

1 mole of beryllium hydroxide reacts with 2 moles of hydrochloric acid to produce 1 mole of beryllium chloride and 2 moles of water.

Hence, the equations showing amphoteric nature of beryllium hydroxide is given above.