Amplitude of 5 + 2 i
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Use the form a⋅cos(bx−c)+d
Given equation is y=(52)cos(x2)
In this equation
a=52,b=12,c=0,d=0
Amplitude = a=52
Period =2πb=2π12=4π
Phase shift = c/b = 9
Vertical shift = d = 0
graph{(5/2) cos (x/2) [
-10, 10, -5, 5]}
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