Question

amplitude of oscillation of particle in shm is√3cm the displacement from mean position at which it's PE&KE are in ratio 1:2 is

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Answer 1

Answer:

PE=

2

1

mω

2

x

2

KE=

2

1

mω

2

(A

2

−x

2

)

∴

KE

PE

=

2

1

∴

x

2

A

2

−x

2

=2

x

2

A

2

=3

x

2

3

=3

x

2

=1

x=1