Question

Amplitude of waves observed by two light sources
of same wave length are a and 2a and have a phase
difference of a between them. Then minimum
intensity of light will be proportional to :
(1) 0 (2) 5a² (3) a² (4) 92²​

Answer 1

Answer:

3

Explanation:

3 a2 because Imin= (2a-a)2=a2