Physics, asked by shailpatel406, 8 months ago

Amplitude of waves observed by two light sources of same wave length are a and
2a and have a phase difference of between them. Then minimum intensity of light
will be proportional to :​

Answers

Answered by GamiGargi
0

answer : a²

amplitude of waves observed by two light sources of same wavelength are a and 2a. and having phase difference between them is π. we know, intensity of light is directly proportional to square of its amplitude. so, minimum intensity of light will be proportional to a².

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