Question

Amrit buys some pens at a price of 10 per pen. He also buys an equal number of
pencils at a price of 35 per pencil
. By selling them, he makes a 20% profit on pens
and 8% profit on pencils. At the end of the day, all pens and pencils are sold
out and his profit amounts to ₹240. Find the number of pens he had purchased.​

Answer 1

Answer:

hope it helps you!!

Step-by-step explanation:

let the number of pens and pencils he had purchased be x.

According to question

CP of total pen and total pencil = 10x+34x = 44x

Profit on pen and pencils = 20%+8% = 28%

we know,

Profit amount = profit percent of C.P

₹240 = 28% of 44x

or, 240 = 28/100 × 44x

therefore x = 19

the number of pens he had purchased is 19

Answer 2

Step-by-step explanation:

Amrit buys some pens at a price of ₹ 10 per pen.

Cost Price of pens = 10*n

He also buys an equal number of pencils at a price of ₹ 5 per pencil.

Cost Price of Pencils = 10*5 = 50

By selling them, he makes 20% profit on pens and 8% profit on pencils.

Selling Price = 120/100*10*n + 108/100*50

At the end of the day, all pens and pencils are sold out and his profit amounts to ₹240.

Profit = SP - CP

240 = \frac{20}{100} \times 10 \times n + \frac{8}{100} \times 50240=

100

20

×10×n+

100

8

×50

\begin{gathered}240 - 4 = 2n \\ n = 118\end{gathered}

240−4=2n

n=118

The number of pens he had purchased = 118.