Math, asked by 1987haricnair1987, 8 months ago

Amrita buys 5 tickets in a raffle where 95 tickets are sold altogether. Find the probability of her winning both FIRST and SECOND prizes.

Answers

Answered by siddharthsingana
0

Answer:

2/893

Step-by-step explanation:

The probability of her winning first prize only = 5/95

And the probability of her winning second prize only = 5/94

(since the first prize was won already by soeone else, subtract that from the total tickets i.e, 95-1 = 94)

Now, the probabilty of her winning both the first and second prize =

         5/95 x 4/94 = 2/893

(since the first prize is won by her already, subtract that one number from the total tickets and the tickets that she has. Now for her to win the 2nd prize, the probability becomes (5-1)/(95-1) = 4/94 )

Hence the final answer is 2/893.

Answered by GulabLachman
0

The probability of winning both first and second prize is 2/893

Given:

Tickets bought = 5

Tickets already sold = 95

To Find:

Probability of winning both first and second prize.

Solution:

Probability of her winning first prize only = 5/95

Now,

As the first prize has already been won by someone, therefore total tickets = 95 - 1 = 94

Since one ticket has also been used, thus = 5 - 1 = 4

Probability of her winning second prize only = 4/94

Similarly,

Probability of her winning both the first and second prize =

5/95 x 4/94

= 1/19  x 2/47

= 2/893

Answer: The probability of winning both first and second prize is 2/893

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