Math, asked by RONITBHURE, 5 months ago

amsn's age is three times his son's age . ten years ago he was five times his son's age find their presant age​

Answers

Answered by Anonymous
1

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Answered by RITESHPRATHIPATI
0

Let us take Amsn's son's present age as x

3x=Amsn's age

Amsn's son's age before 10 years will be x-10

So amsn's age before 10 years will be 5(x-10)=5x-50

10 years after 5x-50=3x

Therefore 5x-50+10=3x

5x-40=3x

5x=3x+40

5x-3x=40

2x=40

x=40/2

 =20

Amsn's age = 3x

                   = 3*20=60

So the final Answer=

Amsn's age is 60 and his son's age is 20

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