Question

amswer the following attachment

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Answer 1

Center of circle

The center of a circle is the center point in a circle from which all the distances to the points on the circle are equal. This distance is called the radius of the circle. Here, point P is the center of the circle.

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Answer 2

Understand it by this question :—

★ In the adjoining figure, O is the centre of a circle. If AB and AC are chords of the circle such that AB = AC, OPLAB and OQLAC, prove that PB = QC

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It is given that AB = AC

Dividing the equation by 2

We get

1/2 AB = 1/2 AC

Perpendicular from the centre of a circle to a chord bisect the chord MB = NC... (1)

We know that the equal chords are equidistant from the centre if the circle OM = ON and OP = OQ

Subtracting both the equation

OP - OM = OQ - ON

So we get ,

PM= QN... (2)

Consider ∆MPB and ∆NQC ,

We know that

angle PMB= angle LQNC = 90°

By SAS congruence criterion

ΔΜΡΒ ≈ ΔNQC

PB = QC (c.p.c.t)

Therefore, it is proved that PB = QC

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★ Note :— The process is same . U only need to see this and solve accordingly !

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