Question

amswer these question immediately its very argent plxxx​

Answer 1

Answer:

6)=Here, the vaue of AC=root41cm

7)=In this question, the perimeter of Rhombus is 68cm.

Step-by-step explanation:

6.)=Here, According to given question,

=ABC is a right triangle, right-angled at B.

=AB=4cm, =BC=5cm

=So, by applying pythagoras theorem, we get

=(AB)^2+(BC)^2=(AC)^2

=(AC)^2=(5)^2+(4)^2

=(AC)^2=25+16

=(AC)^2=41

By doing square root on both sides, we get,

=AC=root(41)cm

7.)=As given in question,

=Let the diagonals be d1 and d2 respectively,

=So, =d1=16cm, d2=30cm

Now, Perimeter of Rhombus when diagonals are given=2×root[(d1^2)+(d2^2]

=Perimeter=2×root[(16)^2+(30)^2]

=2×root[256+900]

=2×root(1156)

=2×34 (By doing square root of 1156)

=68cm

Hence, the perimeter of this Rhombus is 68cm.

Thank you.

Answer 2

Answer:

bhai maine like kar diya hai Sare answer per tum bhi Sare answer per like kar do