amswer this showing full method plzz
no spam plzzz
Attachments:
Answers
Answered by
1
Q1..√176+√2401=√176+49=√225=15 Ans.
Q2..If we take m²+ 1 = 6, then m² = 5
The value of m will not be an integer.If we take m² − 1 = 6, then m² = 7
Again the value of m is not an integer.Let 2m = 6m = 3
Therefore, the Pythagorean triplets are 2 × 3, 32 − 1, 32 + 1 or 6, 8, and 10.
Q3..x+4=8⇒x=4∴√x²=√4²=√16=4 Ans.
Q4..√x=5 By squaring both side x=25 ∴x²=25²⇒x²=625
Q5..Area of square field=441 m²
Area=side²
441=a²⇒a=√441=21
∴Perimeter=4a=4*21=84 m
Q6..Let the breadth be x
legth=2x
Area of ractangle=l*b
2450=2x*x
2450=2x²
2450/2=x²
1225=x²
x=35 m
2x=35*2=70 m
∴ Perimeter=2(l+b)
=2(35+70)
=2(105)
=210 m
.
Q7..√15625=125
√156.25=12.5
√1.5625=1.25
Hence, √156.25+√1.5625=12.5+1.25=13.75
Q8..√2304=48 and √1764=42
√0.2304=0.48 and √0.1764=0.42
∴√0.2304+√0.1764/√0.2304-√0.1764=0.48+0.24/0.48-0.42 =0.9/0.06=15 Ans
Mark me as Brainliest if it helps you!!!!!!!
Q2..If we take m²+ 1 = 6, then m² = 5
The value of m will not be an integer.If we take m² − 1 = 6, then m² = 7
Again the value of m is not an integer.Let 2m = 6m = 3
Therefore, the Pythagorean triplets are 2 × 3, 32 − 1, 32 + 1 or 6, 8, and 10.
Q3..x+4=8⇒x=4∴√x²=√4²=√16=4 Ans.
Q4..√x=5 By squaring both side x=25 ∴x²=25²⇒x²=625
Q5..Area of square field=441 m²
Area=side²
441=a²⇒a=√441=21
∴Perimeter=4a=4*21=84 m
Q6..Let the breadth be x
legth=2x
Area of ractangle=l*b
2450=2x*x
2450=2x²
2450/2=x²
1225=x²
x=35 m
2x=35*2=70 m
∴ Perimeter=2(l+b)
=2(35+70)
=2(105)
=210 m
.
Q7..√15625=125
√156.25=12.5
√1.5625=1.25
Hence, √156.25+√1.5625=12.5+1.25=13.75
Q8..√2304=48 and √1764=42
√0.2304=0.48 and √0.1764=0.42
∴√0.2304+√0.1764/√0.2304-√0.1764=0.48+0.24/0.48-0.42 =0.9/0.06=15 Ans
Mark me as Brainliest if it helps you!!!!!!!
Similar questions