Question

Amy's father is seven times as old as she is. One year ago, he was nine times as old as Amy. Find their present ages.

Pretty pleaasee with a cherry on top, put your solutions :D

Answer 1

Let Amy's present age be x.
Then, her father's age is 7x
One year ago,
$7x - 1 = 9 \times (x - 1) \\ 7x - 1 = 9x - 9 \\ 2x = 8 \\ x = 4$
Thus, Amy's age is 4 years and father's age is 7×4 = 28 years