Question

an
15. Two equal forces 10 N each act at right angles to each other
Find the magnitude and direction of the resultant If that
produces the same effect as the two forces.
(Ans : 14.42, 45°N
116. A single force of 10 N is resolved into two concurrent forces of
6 N each. Find the angle between them.
(Ans : 67" 6' 1
7. The resultant of two given forces is equal to each of the forces,
Find the angle between them.
(Ans : 120°)
Convert the force of 10 kg into Newton. (April/May. 2015)​

Answer 1

Answer:

ans 120

hope this is brainlist

mark as brainlist

Answer 2

$\green{\tt{\therefore{Simple\:Interest=432\:rupees}}}$

Given :-

• $\sf Compound \: Interest(C.I) = 246 \: rupees$

• $\sf Time(t) = 2 \: years$

• $\sf Rate\% = 5\%$

To Find :-

• $\sf Simple \: Interest(S.I) = ?$

Solution :-

$\small\underline{\pmb{\sf \:According \: to \: the \: question :-}}$

$\qquad\leadsto\quad \sf \green{C.I= A - p }$

$\qquad\leadsto\quad \sf 246 = A - p$

$\qquad\leadsto\quad\sf A = 246 + p$

$\qquad\leadsto\quad\sf A= p(1 + \frac{r}{100} )^{t}$

$\qquad\leadsto\quad\sf 246 + p = p \times (1 + \frac{5}{100} )^{2}$

$\qquad\leadsto\quad\sf 246 + p = p \times (1 + 0.05)^{2}$

$\qquad\leadsto\quad\sf \sf 246 + p = p \times 1.1025$

$\qquad\leadsto\quad\sf\sf 246 = 1.1025p - p$

$\qquad\leadsto\quad\sf 246 = 0.1025p$

$\qquad\leadsto\quad\sf p = \frac{246}{0.1025}$

$\green{ \qquad\leadsto\quad \sf p = 2400 \: rupees}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

$\qquad$ ☀️$\sf Principal = 2400 \: rupees$

$\qquad$ ☀️$\sf Rate\% = 6\%$

$\qquad$ ☀️$\sf Time = 3 \: years$

$\small\underline{\pmb{\sf \:Putting \: the \: values :-}}$

$\qquad\leadsto\quad\sf \pink{S.I= \frac{p \times r \times t}{100}}$

$\qquad\leadsto\quad\sf S.I= \frac{2400 \times 6 \times 3}{100}$

$\qquad\leadsto\quad\sf S.I = 24 \times 6 \times 3$

$\qquad\leadsto\quad\sf \pink{\sf S.I = 432 \: rupees}$

$\therefore\:\underline{\textsf{Simple interest is \textbf{ 432 \: rupees}}}.$