CBSE BOARD XII, asked by sanjayriorao, 1 year ago

An 18-m-long steel wire of 5-mm diameter is to be used in the

manufacture of a prestressed concrete beam. It is observed that

the wire stretches 45 mm when a tensile force P is applied. Know-

ing that E 5 200 GPa, determine (a) the magnitude of the force P,

(b) the corresponding normal stress in the wire.​

Answers

Answered by amanabbassaiyed
0

iska jawab meko nahi aata

Explanation:

bhai meko nai aata

Answered by Anonymous
2

A 18m long steel wire of 5mm dia, is stretched by a tensile force P, the wire stretches 45mm. The tensile stress developed in the wire is 500 MPa or 500 N/mm^2.

1) From definition, we know,

stress (σ) = E * ε (longitudinal strain)

2) ε = 0.045/18

3) stress (σ) = 200 * ( 0.045/18 ) = 500 MPa.

4) Again stress (σ) = P/A, So

Load P = stress (σ) * A = 500 * (π / 4) * 5^2 = 9812.5 N = 9.812 KN.

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