An 18-m-long steel wire of 5-mm diameter is to be used in the
manufacture of a prestressed concrete beam. It is observed that
the wire stretches 45 mm when a tensile force P is applied. Know-
ing that E 5 200 GPa, determine (a) the magnitude of the force P,
(b) the corresponding normal stress in the wire.
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A 18m long steel wire of 5mm dia, is stretched by a tensile force P, the wire stretches 45mm. The tensile stress developed in the wire is 500 MPa or 500 N/mm^2.
1) From definition, we know,
stress (σ) = E * ε (longitudinal strain)
2) ε = 0.045/18
3) stress (σ) = 200 * ( 0.045/18 ) = 500 MPa.
4) Again stress (σ) = P/A, So
Load P = stress (σ) * A = 500 * (π / 4) * 5^2 = 9812.5 N = 9.812 KN.
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