Question

An 18000kg van is moving with a speed of 15m/s^1. If superman is to stop the van in 0.5s, what average force will he need to exert on the van?

Answer 1

Answer:

5,40,000 Newtons (opposite direction of van)

Explanation:

Given :

• Mass of the van = 18000 kg's

• Initial velocity of the van = 15 m/s

• Final velocity of the van = 0 m/s

• Time taken to stop the van = 0.5 seconds

To find :

• Force exerted by superman to stop the van

Force = Mass (final velocity - Initial velocity) / time

Force = 18000(0-15)/0.5

Force = 18000(-15)/0.5

Force = - 5,40,000 Newtons

The force exerted by superman in the direction of the motion of the van to stop it is equal to - 5,40,000 Newtons

Answer 2

Gɪᴠᴇɴ :-

• Mass (m) = 18000 kg
• Initial velocity (u) = 15 m/s
• Final velocity (v) = 0. -(Van At rest)
• Time(t) = 0.5 s

ᴛᴏ ғɪɴᴅ :-

• Force (F) required to stop van

sᴏʟᴜᴛɪᴏɴ :-

We know that,

➦ Force = Mass × Acceleration

➦ F = ma

On putting above given values in it, we get,

↬ F = 18000 × ( v - u) /t

↬ F = 18000 × (0 - 15)/0.5

↬ F = 18000 × -15/0.5

↬ F = 18000 × -30

↬ F = -540000 N

Hence,

Force required to stop the van should be 540000 N and (-) sign shows that force must be applied in opposite direction of motion of van.