Question

An 25 litres cylinder contains a mixture of oxygen and
nitrogen, the volume of oxygen being 25% of the total
volume. A few litres of the mixture is released and replaced
by nitrogen for two times. As a result, the oxygen content
becomes 9% of the total volume. How many litres of mixture
is released each time ?​

Answer 1

Step-by-step explanation:

at first the amount of oxygen is 40% of 12l =4.8l

At the end the amount is 10% of total volume = 10% of 12l = 1.2l

So, the change in volume is (4.8-1.2)l = 3.6l

so, we can say that 3.6l of oxygen was released at 2 times, hence at once (3.6/2)l = 1.8l of oxygen was released

Answer 2

Concept Introduction:

With an atomic number of $8$ and the chemical symbol O, oxygen is the eighth chemical element. It belongs to the periodic table's chalcogen group, is a very sensitive nonmetal, and an oxidising agent that easily produces oxides with most components as well as other compounds.

Given, An $25$ litres cylinder contains a mixture of oxygen and nitrogen, the volume of oxygen being $25$% of the total volume. A few litres of the mixture is released and replaced by nitrogen for two times. As a result, the oxygen content becomes $9$% of the total volume.

To find, how many litres of mixture is released each time.

Solution:

According to the problem,

At first the amount of oxygen is $40$ % of $12 L$

At the end the amount is $10$% of total volume = $10% of 12L = 1.2L$

So, the change in volume is $(4.8-1.2)L = 3.6L$

so, we can say that $3.6L$ of oxygen was released at $2$ times, hence at once$(3.6/2) L= 1.8L$ of oxygen was released

Final Answer:

$1.8 L$ oxygen was released.

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