Question

an^2A + cot^2A= sec^2A*cosec^2A - 2

plz help me answer this

No scam answers plz .​

Answer 1

Step-by-step explanation:

LHS=tan^2 A+cot^2A

=sin^2A /cos^2A +cos^2 A/sin^2 A

=sin^4A +cos^4A /cos^2 A. sin^2 A

=(sin^2 A+cos^2A) ^2 - 2sin^2 A. cos^2 A/cos^2 A. sin^2 A

=(1) ^2 - 2sin^2 A. cos^2 A/cos^2 A. sin^2 A

=1-2sin^2 A. cos^2 A/cos^2 A.sin^2 A

=(1/cos^2 A. sin^2 A)-(2/2sin^2 A. cos^2 A)

= 1/cos^2 A. 1/sin^2 A-2

=sec^2 A. cosec^2 A-2

RHS=sec^2 A. cosec^2 A-2

So LHS=RHS(proved).

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