an=3n-2 then,the value of a7+a8 is
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Step-by-step explanation:
Here we have to just substitute the value of n.
Finding a₇,
\sf{\implies a_7 = (3\times 7)-2}⟹a
7
=(3×7)−2
\sf{\implies a_7 = 21-2}⟹a
7
=21−2
\sf{\implies a_7 = 19}⟹a
7
=19
Finding a₈,
\sf{\implies a_8 = (3\times 8)-2}⟹a
8
=(3×8)−2
\sf{\implies a_8 = 24-2}⟹a
8
=24−2
\sf{\implies a_8 = 22}⟹a
8
=22
Finding a₇+a₈,
\sf{\implies a_7+a_8 = 19+22 }⟹a
7
+a
8
=19+22
\sf{\implies a_7+a_8 = 41 }⟹a
7
+a
8
=41
Therefore,
\boxed{\sf{\therefore a_7+a_8 = 41 }}
∴a
7
+a
8
=41
I hope this helps
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