Question

an=4,d=2,sn=-14 find n and a​

Answer 1

Answer:

we know that you can use formula An = a+ (n-1)d

so we put value 4=a+(n-1)2

so the a=3-n

we can put in

4=n-3+(n-1)2

7=n+2n-2

9= 3n

n=3

hope it helps have a nice day

Answer 2

Answer:

An=a+(n-1)d=4

a+(n-1)2=4 (substitute d=2)

a+2n-2=4

a+2n=6

a=6-2n

Sn=n/2(2a+(n-1)d)

-14=n/2(2(6-2n)+(n-1)2) (substitute a=6-2n,d=2)

-14=n/2(12-4n+2n-2)

-14=n/2(10-2n)

-14=n(5-n)

5n-n^2=-14

n^2-5n-14=0

n^2-7n+2n-14=0

6-2n(n-7)+2(n-7)=0

(n-7)(n+2)=0

n=7,-2

n can't be negative

therefore n=7

a=6-2n (substitute n=7)

a=6-2(7)=6-14=-8