An 4-sided die is thrown 5 times. Find the probability that a “2” never appears.
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Answer:
1024/3125
Step-by-step explanation:
First time 2 never appears: 4/5
Second time: 4/5
3rd time: 4/5
4th time: 4/5
5th time: 4/5
4/5 * 4/5 * 4/5 * 4/5 * 4/5 = 1024/3125.
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