Math, asked by vinaygudavalli3777, 6 months ago

An 4-sided die is thrown 5 times. Find the probability that a “2” never appears.

Answers

Answered by rickinuba
0

Answer:

1024/3125

Step-by-step explanation:

First time 2 never appears: 4/5

Second time: 4/5

3rd time: 4/5

4th time: 4/5

5th time: 4/5

4/5 * 4/5 * 4/5 * 4/5 * 4/5 = 1024/3125.

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