an=4 Sn=14 d=2find n and a
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Sn=14,d=2
sn=n/2(2f+(n-1)d)
14=n/2(2f+2n-2)
28=n(2f+2n-2)
28/n=2f+2n-2
28/n+2/1=2f+2n
28+2n/2=14+n
14+n=2f+2n
14=2f+2n-n
14=2f+n
14/2=f+n
7=f+n
n=4 & a=3
checking..sn=n/2(a+an)
= 4/2(3+4)
=2×7=14
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