An 8.0 L of sample at 0° C and 5.6 atm of pressure contains 2.0 moles of a gas. If more 1.0 mole
of gas at the same temperature and pressure is added, calculate the final volume.
Answers
Answered by
1
20ltrs
Explanation:
pv=nrt
if 1 mole is added ot becomes 3 moles
5.6×V=3×0.082×273
V=12
final volume = 12+8=20 ltr
Answered by
1
Answer:
12L
Explanation:
n=PV/RT by this equation,
total n= 2+1=3,
then,
3= 5.6*v/0.0821*273 [where,gas constant R=0.0821 and absolute temperature =0+273 ,as 0 °c=273 k
answer is 12l
I think it may help you
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