An 8-bit computer has a 16-bit address bus. The first 15 lines of address are used to select a bank of 32K bytes of memory. The higher order bit of address is used to select a register which receives the contents of the data bus? Explain how this configuration can be used to extend the memory capacity of system to eight banks of 32 K bytes each, for a total of 256 bytes of memory
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ans-Explanation: When it comes to the processor we get to see that it generally makes a seletcion of the external register that has an address of 8000 units or hexadecimal. Each of the separate bank then comes with a 32K byte which has a definite address of 0000-7 FFF.
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