Question

an 8 cm long wire is to be bent into a rectangle can a rectangle with diagonal 2cm be made from it ?why?​

Answer 1

Answer:

no it is not possible

Step-by-step explanation:

see the image above

Answer 2

Answer:

2 ( a + b ) = 8

=> a + b = 4

=> a = ( 4-b )

therefore,

a^2 + b^2 = 2

=> ( 4-b)^2 + b^2 = 2

=> { 16 + b^2-2.( 4 ) .( b )} + b^2 = 2

=> 16 + 2b^2 - 8b = 2

=> 2b^2- 8b + 14 = 0

=> b^2- 4b + 7 = 0

=> b = { (√11 ) -2 } or { -( √11 ) -2 }

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