Question

An 8-digit number 4252746B leaves
remainder 0 when divided by 3. How many
values of B are possible ?
(a)
2
(b)
3
(c)
(d)
4
6​

Answer 1

Answer:

(b)=3

because when we add all the numbers 4+2+5+2+7+4+6+x= divisible by 3

30+3= can divisible by 3

33= can divisible by

Answer 2

Option B - the possible values of B are 3.

Step-by-step explanation:

Given : An 8-digit number 4252746B leaves  remainder 0 when divided by 3.

To find : How many  values of B are possible ?

Solution :

By property of divisibility of 3,

The sum of the number is divisible by 3.

An 8-digit number 4252746B leaves  remainder 0 when divided by 3.

So, 4+2+5+2+7+4+6+B is divisible by 3.

i.e. 30+B is divisible by 3.

Then accordingly B can be 3,6 or 9.

Therefore, the possible values of B are 3.

So, Option b is correct.

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An 8 digit number 4252746b leaves remainder 0 when divided by 3. How many values of b are possible.

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