Question

an 8 foot metal guy wire is attached to a broken stop sign to secure it's position until repairs can be made. attached to a stake in the ground,the guy makes an angle of 51° with the ground.how far from the foot of the stop sign is the stake, to the nearest tenth of a foot?



It is from trigonometry
please solve ,I need immediately , I will give you more points and markbas brainlist .don't give wrong answers ,​

Answer 1

Answer:

$\huge\fbox\mathbf\blue{ \: Answer \: }$

Given length of wire = 8 foot

Angle made by ground = 51°

To find -: Base distance

Cos 51° = b/h

Cos 51° = x/8

=> x = 8×Cos 51°

=> x = 5.03 feet

Then we round off to nearest 10

Thus,Answer is 5.0 ft.

Answer 2

Given length of wire = 8 foot

Given length of wire = 8 footAngle made by ground = 51°

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distance

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/h

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/hCos 51° = x/8

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/hCos 51° = x/8=> x = 8×Cos 51°

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/hCos 51° = x/8=> x = 8×Cos 51°=> x = 5.03 feet

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/hCos 51° = x/8=> x = 8×Cos 51°=> x = 5.03 feetThen we round off to nearest 10

Given length of wire = 8 footAngle made by ground = 51°To find -: Base distanceCos 51° = b/hCos 51° = x/8=> x = 8×Cos 51°=> x = 5.03 feetThen we round off to nearest 10Thus,Answer is 5.0 ft.