An 8 kg block accelerates uniformely from rest to a velocity of 4 m per sec in 40 sec. The instantaneous power at the end of 8 sec is
A. 0.64 W
B. 0.32 W
C. 0.16 W
D. 0.08 W
Answers
Answered by
3
hey mate
here is your answer
given:
mass=8 kg
initial velocity=0
final velocity=4 m/s
time=40 s
acceleration=v-u/t
=40-0/40
=1 m/s²
as the body accelerates uniformly , therefore the acceleration at any instant is 1 m/s²
given:
time = 8 s
acceleration=1 m/s²
mass=8 kg
displacement of the body in 8 s=1/2at²
=1/2*1*(8)²
=32 m
therefore power=work /time
=force * displacement/time
= ma*32/8
=8*1*4
=32 watt (answer)
#be brainly
here is your answer
given:
mass=8 kg
initial velocity=0
final velocity=4 m/s
time=40 s
acceleration=v-u/t
=40-0/40
=1 m/s²
as the body accelerates uniformly , therefore the acceleration at any instant is 1 m/s²
given:
time = 8 s
acceleration=1 m/s²
mass=8 kg
displacement of the body in 8 s=1/2at²
=1/2*1*(8)²
=32 m
therefore power=work /time
=force * displacement/time
= ma*32/8
=8*1*4
=32 watt (answer)
#be brainly
Anonymous:
welcome
Answered by
3
32 watt
that is your answer
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