Question

An 8-pole de generator running at 1200rpm and with a flux of 25 m Wb per pole generates
440 V. Calculate the number of conductors, if the armature is (i) lap-wound (ii) wave
wound.​

Answer 1

Answer:

vhgh you g è Mami ji tusi great ho

Step-by-step explanation:

jjmkjs in this case it is located by huk

Answer 2

Given : A 8-pole dc generator running at 1200rpm and with a flux of 25 mWb per pole generates 440 V.

To find : The number of conductors, if the armature is (i) lap-wound (ii) wave wound.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the number of conductors)

In case of lap wound :

Number of poles (P) = 8

Number of parallel paths (A) = Number of poles (P) = 8 (as it is lap wound)

Flux per pole (φ) = 25 mWb = (25 × 10⁻³) Wb

Speed (N) = 1200 rpm

Induced EMF = 440V

Number of conductors (Z) = ? (unknown)

Now, we know that :

Induced EMF = (φZNP)/60A

or,

440 = (25 × 10⁻³ × Z × 1200 × 8)/(60 × 8)

0.5 × Z = 440

Z = 440/0.5

Z = 880

Number of conductors (Z) = 880

In case of wave wound :

Number of poles (P) = 8

Number of parallel paths (A) = 2

Flux per pole (φ) = 25 mWb = (25 × 10⁻³) Wb

Speed (N) = 1200 rpm

Induced EMF = 440V

Number of conductors (Z) = ? (unknown)

Now, we know that :

Induced EMF = (φZNP)/60A

or,

440 = (25 × 10⁻³ × Z × 1200 × 8)/(60 × 2)

2 × Z = 440

Z = 440/2

Z = 220

Number of conductors (Z) = 220

Hence, the number of conductors are 440 and 220, in case of lap wound and wave wound, respectively.