Question

. An 8 Ω resistance wire is doubled by stretching. Calculate the value of the new resistance offered by the wire. how​

Answer 1

Answer:

4 ×8=32

Explanation:

when a wire is streched then the area of cross section will decrease and the volume remains constant through out the wire ,,and thus the area= πr^2 so radius will decrease 4 times and resistance is indirectly proportional to radius thus resistance became 4times the initial value.