Question

An 800 kg police boat slows down uniformly from 50 km/h [E] to 20 km/h [E] as it enters a harbour. If the boat slows down over a 30 m distance, what is the force of friction on the boat? Pls add the steps also. Don't answer if you cannot help unless I will report you

Answer 1

Answer:

Answer:

The acceleration of the boat is found from the equation:

v

2

= v0

2

+ 2(a×s), where v – the final velocity, v0 – the initial velocity and s – the distance.

After converting the velocities into m/s: v0 = 50 km/h = 50000/3600 m/s = 13.89 m/s and v = 20 km/h =

20000/3600 m/s = 5.56 m/s, the acceleration equals:

a = (v2

- v0

2

)/(2s) = (30.86 – 192.93 )/60 m s-2 = -2.701 m s-2

The force of friction is defined:

F = m×a = 800 kg × (-2.7 m s-2) = -2160.96 N

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