Math, asked by angleranip6k6rd, 1 year ago

An 800 ml mixture of syrup and water contains
25% syrup. How much syrup (in ml) should be
added to this mixture to increase syrup
concentration to 40%

Answers

Answered by ancyvarghese

Answer:

200 ml

Step-by-step explanation:

quantity of syrup in initial solution = 200 ml (.25*800)

quantity of water in initial solution = 600 ml (800-200)

ratio of syrup to water =1:3

new ratio required = 40:60 = 2:3

so if x amount of syrup is added, the ratio should become 2:3

200+x = 2

600 3

hence by cross multiplying

600+ 3x= 1200

3x= 600, x= 200

Hence add 200 ml of syrup, the solution quantity becomes 1000ml. syrup concentration will be 200+200 = 400/1000= 40%

ancyvarghese: please rate my answer

angleranip6k6rd: 2. Three boys and five girls are to form a line. What
-is the number of ways in which they can be
arranged if the first is a boy and the last is a girl?

angleranip6k6rd: Hey search this question and answer please

ancyvarghese: cant find the question.. but this might be the answer

ancyvarghese: There are 3 ways to choose the boy at one end and 5 ways to choose the girl at the other. The other 6 people can be arranged in
6!=120
6!=120
ways. In all,
3×5×120=1800
3×5×120=1800
.

ancyvarghese: hope this helps you

angleranip6k6rd: find the average speed of motorist who completed first 60 miles with an average speed of 40 mph and next 30 miles with an average speed of 30 mph

angleranip6k6rd: Hey answer this question please

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An 800 ml mixture of syrup and water contains 25% syrup. How much syrup (in ml) should be added to this mixture to increase syrup concentration to 40%

Answers

An 800 ml mixture of syrup and water contains
25% syrup. How much syrup (in ml) should be
added to this mixture to increase syrup
concentration to 40%