An 8000kg engine pulls a train of 5 wagons,each wagon of mass 2000kg,along a horizontal track.If the engine exerts a force of 40000N and the track offers a friction force of 5000N
calculate
i)the net accelerating force,
ii)the acceleration of the train,and
iii)the force of wagon 1 on wagon 2
please solve it step by step and give me the answer fast
Answers
Answered by
0
Explanation:
व्हाट इज द आंसर ऑफ है क्या चंदू आई नाउ
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Answer:
Explanation:
Mass of engine=8000kg
No. of wagons = 5
Mass of each wagon= 2000kg
Total mass of wagon = (5*2000)kg=10000kg
Total mass of train = [ Total mass of engine+ Total mass of wagons] = (10000+8000)kg= 18000kg
Now,
Force exerted by engine =40000N
Friction force of track = 5000N
a) net accelerating force=(40000-5000)N
( Ans)
b) the acceleration of the train :-
==>F=ma
==>35000N=18000kg* a
==>a= 35000N/18000kg= 1.944ms-²( Ans )
c) ==>F=ma
==>F=(8000*1.944)=15552N (Ans)
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