Question

An 80kg man stand on spring balance in elevator.When it start fo move the scale read 700n .What is acgeleration

Answer 1

-> the acclereation of elevator(g=10m/s)

Nett force on the man body = 80 kg * 10m/s^2 - 700 N = 100 N Downward.

Use, F = m * a

100 N = 80 kg * a

a = 1.25 m/s^2 Downward.

Hope i've helped