Question

An 80kg men stands on a spring balance in an elevator when it starts to move the scale read 700 what is the acceleration of the elevator

Answer 1

Nett force on the man body = 80 kg * 10m/s^2 - 700 N = 100 N Downward. 
Use, F = m * a 
100 N = 80 kg * a 
a = 1.25 m/s^2 Downward.

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Answer 2

Answer:

answer is 1.25m/s²

Explanation:

reading of the spring balance = m(g bar - a bar )

where a bar is acceleration of the elevtor

here m(g bar - a bar )=700N

80(10-a)=700N

10-a=70/8

a=10-8.75

that equal to 1.25m/s²

acceleration of the elevator is 1.25m/s²

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