Question

an
A motor cycle moving with a speed
of 5 m/s is subjected to
acceleration of 0.2 m/s2. Calculate
the speed of the motor cycle after 10
second, and the distance travelled in
this time.​

Answer 1

Answer:

given :

u = 5m/s

a = 0.2m/s^2

t = 10s

s = ?

Explanation:

to find distance , apply 2nd equation of motion ;

s = ut + at^2

s = 5m/s * 10s + 1/2 * 0.2m/s^2 * ( 10s ) ^2

s = 50m + 1/2 * 0.2m/s^2 * 100s^2

s = 50m + 2/20 m * 100

s = 50m + 10m

s = 60m

Answer 2

Explanation:

U=5m/sec^2

a=0.2m/sec^2

t=10sec

USING FIRST EQUATION OF MOTION

v=u+at

v=5+0.2×10

v=7m/sec

FINAL VELOCITY=7m/s

2nd EQUATION if motion

s=ut+1/2 at^2

s=5×10+1/2×2/10×10×10

s=50+10

s=60

DISTANCE =60