Question

An a.P consists of 50 term fo which 3 term is 12 and the last term is 106. Find 29 them

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

given: A50  = 106, A3 = 12, n 50, A29 = ?

An = A + (n-1)d

A50 = A + 49D

A + 49D = 106  -> EQ 1

A3 = A + 2D

A +2D = 12 -> EQ 2

FROM 1 AND 2

BY SOLVING IT

WE GET, D = 2

SUB IN EQ 2

A + 2 × 2 = 12

A = 8

NOW,

A29 = 8+ 28 × 2

A29= 8 + 56

A29= 64

this is the answer

i hope you understood.