An A. P consists of 50 terms of which 3rd term is 12 and last term is 106. Find the 29th term
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2
Answer:
64
Step-by-step explanation:
Let a , d are first term and common
difference of an A.P
nth term = Last term = a + ( n - 1 )d
an = a + ( n - 1 )d
Now ,
It is given that ,
Third term = 12
a + 2d = 12 ------( 1 )
Last term = 106
a + 49d = 106 ---( 2 )
Subtract ( 1 ) from ( 2 ) , we get
47d = 94
d = 2
Substitute d value in equation ( 1 ) ,
We get
a + 2 × 2 = 12
a = 12 - 4
a = 8
29th term = a + 28d
a29 = 8 + 28 × 2
= 8 + 56
= 64
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