An a.p. consists of 50 terms of which 3rd term is 12 and the last term is 106. find the 29th term
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Answer:
Step-by-step explanation:
An = a+(n-1)d
12 = a+(3-1)d
12=a+2d
A=12-2d
A50=106
106=a+(50-1)d
106=12-2d+49d
106-12=47d
94=47d
D=94/47 = 2
A=12-2d
=12-2×2
=12-4=8
A29=a+(n-1)d
=8+(29-1)2
=8+28×2
=8+56 = 64
Hope it works
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