An A.P consists of 50 terms of which 3rd terms is 12.
the last terms is 106. Find the 29th term of the AP
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Answer:
68
n=50
A3 = 12
a+2d= 12-----------1
A50= 106
a+49d=106--------2
2 - 1
47d= 94
------------d=2
Also, a+ 49d = 106
-------a= 12
therefore, A29 = a + 28d = 12 + 56=68
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